x^2+154x+304=0

Solution for x^2+154x+304=0 equation:

x^2+154x+304=0

a = 1; b = 154; c = +304;
Δ = b2-4ac
Δ = 1542-4·1·304
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(154)-150}{2*1}=\frac{-304}{2}
=-152
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(154)+150}{2*1}=\frac{-4}{2}
=-2
$